The radius of the circle, having centre at (2, 1), whose one of the chord is a diameter of the circle x2 +y2 –2x–6y+6=0

The radius of the circle, having centre at (2, 1), whose one of the chord is a diameter of the circle x2 +y2 –2x–6y+6=0

Anonymous User Maths Circle 22 May, 2020 64 views

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