Let P be the point (1, 0) and Q a point on the locus y2 = 8x. The locus of midpoint of PQ is

A.

x² – 4y + 2 = 0

B.

x² + 4y + 2 = 0

C.

y² + 4x + 2 = 0

D.

y² – 4x + 2 = 0

Anonymous User Maths Two Dimensional Geometry 26 Aug, 2020 54 views

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