The period of revolution of a satellite orbiting Earth at a height 4R above the surface of Earth is x hrs, where R is the radius of earth. The period of another satellite at a height 1.5R from the surface of the Earth is

Anonymous User Physics Gravitation and Projectile 03 May, 2020 1 Answer 63 views




A planet of radius R = 1/10 (radius of Earth) has the same mass density as Earth. Scientists dig a well of 10 depth R5 on it and lower a wire of the same length and of linear mass density 10–3 kg m–1 into it. If the wire is not touching anywhere, the force applied at the top of the wire by a person holding it in place is (take the radius of Earth = 6 × 106 m and the acceleration due to gravity on Earth is 10 ms–2)

Anonymous User Physics Gravitation and Projectile 03 May, 2020 1 Answer 107 views

A satellite is moving with a constant speed V in a circular orbit about the earth. An object of mass m is ejected from the satellite such that it just escapes from the gravitational pull of the earth. At the time of its ejection, the kinetic energy of the object is

Anonymous User Physics Gravitation and Projectile 02 May, 2020 1 Answer 58 views




The time period of a satellite of the earth is 10 hours. If the separation between the earth and the satellite is increased to 4 times the previous value, then what will be the new time period of the satellite?

Anonymous User Physics Gravitation and Projectile 02 May, 2020 1 Answer 56 views