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A shell is fired at a speed of 200 m/s at an angle of 37° above horizontal from top of a tower 80m high. At the same instant another shell was fired from a jeep travelling away from the tower at a speed of 10 m/s as shown. The velocity of this shell relative to jeep is 250 m/s at an angle of 53° with horizontal. Find the time (in sec) taken by the two shells to come closest?

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A shell is fired at a speed of 200 m/s at an angle of 37° above horizontal from top of a tower 80m high. At the same instant another shell was fired from a jeep travelling away from the tower at a speed of 10 m/s as shown. The velocity of this shell relative to jeep is 250 m/s at an angle of 53° with horizontal. Find the time (in sec) taken by the two shells to come closest.

Anonymous User tag : Physics 04 May, 2019 1 Answer 80 views

work

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a body freely falls from certain height onto ground in time t during first 1/3rd of time interval it gains ake1 and during last 1/3 rd of intervalit gains ke2 the ratio of ke1/ke2 is

Anonymous User tag : Physics 02 May, 2019 1 Answer 75 views

1.00 g of a non-electrolyte solute dissolved in 50 g of benzene lowered the freezing point of benzene by 0.40 K. The freezing point depression constant of benzene is 5.12 K kg mol–1. Find the molar mass of the solute

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1.00 g of a non-electrolyte solute dissolved in 50 g of benzene lowered the freezing point of benzene by 0.40 K. The freezing point depression constant of benzene is 5.12 K kg mol–1. Find the molar mass of the solute

Rajkumar Yadav tag : Chemistry 01 May, 2019 1 Answer 109 views

The boiling point of benzene is 353.23 K. When 1.80 g of a non-volatile solute was dissolved in 90 g of benzene, the boiling point is raised to 354.11 K. Calculate the molar mass of the solute. Kb for benzene is 2.53 K kg mol–1

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The boiling point of benzene is 353.23 K. When 1.80 g of a non-volatile solute was dissolved in 90 g of benzene, the boiling point is raised to 354.11 K. Calculate the molar mass of the solute. Kb for benzene is 2.53 K kg mol–1 

Rajkumar Yadav tag : Chemistry 01 May, 2019 1 Answer 113 views

The vapour pressure of pure benzene at a certain temperature is 0.850 bar. A non-volatile, non-electrolyte solid weighing 0.5 g when added to 39.0 g of benzene (molar mass 78 g mol-1). Vapour pressure of the solution, then, is 0.845 bar. What is the molar mass of the solid substance?

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The vapour pressure of pure benzene at a certain temperature is 0.850 bar. A non-volatile, non-electrolyte solid weighing 0.5 g when added to 39.0 g of benzene (molar mass 78 g mol-1). Vapour pressure of the solution,
then, is 0.845 bar. What is the molar mass of the solid substance?

Anonymous User tag : Chemistry 01 May, 2019 1 Answer 156 views

Vapour pressure of chloroform (CHCl3) and dichloromethane (CH2Cl2) at 298 K are 200 mm Hg and 415 mm Hg respectively. (i) Calculate the vapour pressure of the solution prepared by mixing 25.5 g of CHCl3 and 40 g of CH2Cl2 at 298 K and, (ii) mole fractions of each component in vapour phase.

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Vapour pressure of chloroform (CHCl3) and dichloromethane (CH2Cl2) at 298 K are 200 mm Hg and 415 mm Hg respectively. (i) Calculate the vapour pressure of the solution prepared by mixing 25.5 g of CHCl3 and 40 g of H2Cl2 at 298 K and, (ii) mole fractions of each component in vapour phase.

Anonymous User tag : Chemistry 01 May, 2019 1 Answer 2034 views

If N2 gas is bubbled through water at 293 K, how many millimoles of N2 gas would dissolve in 1 litre of water. Assume that N2 exerts a partial pressure of 0.987 bar. Given that Henry’s law constant for N2 at 293 K is 76.48 kbar.

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If N2 gas is bubbled through water at 293 K, how many millimoles of N2 gas would dissolve in 1 litre of water. Assume that N2 exerts a partial pressure of 0.987 bar. Given that Henry’s law constant for N2 at 293 K is
76.48 kbar.

Anonymous User tag : Chemistry 01 May, 2019 1 Answer 1372 views

law of motion

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a mass of 3kg descending vertically downward supports a mass 2 kg by means of light string passing over a pulley at end of 5 sec the string breaks how much higher 2kg mass will go

Anonymous User tag : Physics 30 Apr, 2019 1 Answer 101 views

In a uniform electric field, a cube of side 1 cm is placed. The total energy stored in the cube is 8.85μJ. The electric field is parallel to four of the faces of the cube. The electric flux through any one of the remaining two faces is.

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In a uniform electric field, a cube of side 1 cm is placed. The total energy stored in the cube is 8.85μJ. The electric field is parallel to four of the faces of the cube. The electric flux through any one of the remaining two faces is.

Anonymous User tag : Physics 28 Apr, 2019 1 Answer 211 views

Suppose that two heat engines are connected in series, such that the heat exhaust of the first engine is used as the heat input of the second engine as shown in figure. The efficiencies of the engines are n1 and n2, respectively. The net efficiency of the combination is given by?

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Suppose that two heat engines are connected in series, such that the heat exhaust of the first engine is used as the heat input of the second engine as shown in figure. The efficiencies of the engines are n1 and n2, respectively. The net efficiency of the combination is given by?

Anonymous User tag : Physics 28 Apr, 2019 1 Answer 204 views

A magnet is suspended in such a way when it oscillates in the horizontal plane. It makes 20 oscillations per minute at a place where dip angle is 30 and 15 oscillations per min at a place where dip angle is 60 . Find the ratio of the total earth's magnetic field at the two places?

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A magnet is suspended in such a way when it oscillates in the horizontal plane. It makes 20 oscillations per minute at a place where dip angle is 30 and 15 oscillations per min at a place where dip angle is 60 . Find the ratio of the total earth's magnetic field at the two places?

Anonymous User tag : Physics 26 Apr, 2019 0 Answer 98 views

A simple pendulum is suspended in a lift which 5. is going up with an acceleration 5 m/s2. An electric field of magnitude 5 N/C and directed vertically upward is also present in the lift. The charge of the bob is 1 mC and mass is 1 mg. Taking g = p2 and length of the simple pendulum 1m, the time period of the simple pendulum is

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A simple pendulum is suspended in a lift which 5. is going up with an acceleration 5 m/s^2. An electric field of magnitude 5 N/C and directed vertically upward is also present in the lift. The charge of the bob is 1 mC and mass is 1 mg. Taking g =  and length of the simple pendulum 1m, the time period of the simple pendulum is

Anonymous User tag : Physics 20 Apr, 2019 1 Answer 132 views