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A simple pendulum is suspended in a lift which 5. is going up with an acceleration 5 m/s2. An electric field of magnitude 5 N/C and directed vertically upward is also present in the lift. The charge of the bob is 1 mC and mass is 1 mg. Taking g = p2 and length of the simple pendulum 1m, the time period of the simple pendulum is

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A simple pendulum is suspended in a lift which 5. is going up with an acceleration 5 m/s^2. An electric field of magnitude 5 N/C and directed vertically upward is also present in the lift. The charge of the bob is 1 mC and mass is 1 mg. Taking g =  and length of the simple pendulum 1m, the time period of the simple pendulum is

Anonymous User tag : Physics 20 Apr, 2019 1 Answer 122 views

X-ray diffraction studies show that copper crystallises in an fcc unit cell with cell edge of 3.608×10-8 cm. In a separate experiment, copper is determined to have a density of 8.92 g/cm3, calculate the atomic mass of copper

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X-ray diffraction studies show that copper crystallises in an fcc unit cell with cell edge of 3.608×10-8 cm. In a separate experiment, copper is determined to have a density of 8.92 g/cm3, calculate the atomic mass of copper

Rajkumar Yadav tag : Chemistry 19 Apr, 2019 1 Answer 60 views

A number consists of three digits which are in G.P. the sum of the right hand and left hand digits exceeds twice the middle digit by 1 and the sum of the left hand and middle digits is two third of the sum of the middle and right hand digits. Find the numbers?

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A number consists of three digits which are in G.P. the sum of the right hand and left hand digits exceeds twice the middle digit by 1 and the sum of the left hand and middle digits is two third of the sum of the middle and right hand digits. Find the numbers?

Anonymous User tag : Maths 18 Apr, 2019 1 Answer 362 views

A sounding body emitting a frequency of 150 Hz is dropped from a height. During its fall under gravity it crosses a balloon moving upwards with a constant velocity of 2m/s one second after it started to fall. The difference in the frequency observed by the man in balloon just before and just after crossing the body will be: (given that -velocity of sound = 300m/s; g = 10m/s2 )

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A sounding body emitting a frequency of 150 Hz is dropped from a height. During its fall under gravity it crosses a balloon moving upwards with a constant velocity of 2m/s one second after it started to fall. The difference in the frequency observed by the man in balloon just before and just after crossing the body will be:

Given that -velocity of sound = 300m/s; g = 10m/s2.

(A) 4

(B) 6

(C) 8

(D) 12

Kirti Gulati tag : Physics 16 Apr, 2019 1 Answer 53 views

A passenger is standing d distance away from a bus. The bus begins to move with constant acceleration a. To catch the bus, the passenger runs at a constant speed u towards the bus. What must be the minimum speed of the passenger so that he may catch the bus?

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A passenger is standing d distance away from a bus. The bus begins to move with constant acceleration a. To catch the bus, the passenger runs at a constant speed u towards the bus. What must be the minimum speed of the passenger so that he may catch the bus?

Anonymous User tag : Physics 15 Apr, 2019 1 Answer 82 views

A driver takes 0.30 s to apply the brakes after he sees a need for it. This is called the reaction time of the driver. If he is driving a car at a speed of 54 km/h and the brakes cause a deceleration of 5.0m/s2, find the distance travelled by the car after he sees the need to put the brakes on ?

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A driver takes 0.30 s to apply the brakes after he sees a need for it. This is called the reaction time of the driver. If he is driving a car at a speed of 54 km/h and the brakes cause a deceleration of 5.0m/s2, find the distance travelled by the car after he sees the need to put the brakes on ?

Anonymous User tag : Physics 15 Apr, 2019 1 Answer 61 views

The force of repulsion between two point charges is F, when these are at a distance of 1 m. Now the point charges are replaced by spheres of radii 25 cm having the charge same as that of point charges. The distance between their centres is 1 m, then compare the force of repulsion in two cases.

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The force of repulsion between two point charges is F, when these are at a distance of 1 m. Now the point charges are replaced by spheres of radii 25 cm having the charge same as that of point charges. The distance between their centres is 1 m, then compare the force of repulsion in two cases.

Anonymous User tag : Physics 13 Apr, 2019 1 Answer 680 views

A particle is moving along a straight line along x-axis with an initial velocity of 2 m/s towards positive x-axis. A constant acceleration of 0.5 m/s2 towards negative x-axis starts acting on particle at t=0. Find velocity (in m/s) of particle at t = 2s.

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A particle is moving along a straight line along x-axis with an initial velocity of 2 m/s towards positive x-axis. A constant acceleration of 0.5 m/s2 towards negative x-axis starts acting on particle at t=0. Find velocity (in m/s) of particle at t = 2s.

Rahul Kumar tag : Physics 12 Apr, 2019 1 Answer 61 views

A body is thrown up with a speed 49 m/s. It travels 5 m in the last second of its upward journey. If the same body is thrown up with a velocity 98 m/s, how much distance (in m) will it travel in the last second. (g = 10 m/s2)?

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A body is thrown up with a speed 49 m/s. It travels 5 m in the last second of its upward journey. If the same body is thrown up with a velocity 98 m/s, how much distance (in m) will it travel in the last second. (g = 10 m/s2)?

Rahul Kumar tag : Physics 12 Apr, 2019 1 Answer 80 views